ANSWER: The fresh magnetic push to the a relocation costs is perpendicular in order to its acceleration

4 Tháng Bảy, 2022

ANSWER: The fresh magnetic push to the a relocation costs is perpendicular in order to its acceleration

Then the force will be F=kqvB on the z-guidelines

QUESTION: A number of electrical power is placed by the volts x amps x day. A number of physical opportunity was outlined (or is) by the push x point and that equates to energizing time. Whenever energy is actually changed into mechanized, a force is created by applying current and current (amps). Is this a paradox? Energy was functionally force x go out while you are technical energy is force x range.

ANSWER: 1 V=step 1 J/C and 1 A great=1 C/s, so 1 volt ·amp·second=step 1 Joules=force·distance. No discrepancy, no contradiction. A different way to look at this is that most recent moments voltage was electricity and you may fuel was W=J/s.

Follow-up Matter: I totally understand that step 1 amp try 1 coulomb for every 2nd. I am not sure where step one volt is equal to step 1 joule per coulomb is inspired by otherwise as to why that is right.

ANSWER: New electronic occupation Age is set getting the newest push F felt from the a fee Q separated of the Q. The newest electronic prospective V is understood to be Elizabeth minutes length d more which it serves. V=Ed=Fd/Q=[J/C]

QUESTION: magnetic push for the charge q moving which have acceleration v real BHM singles dating site =qV x B easily observe which fees away from a car or truck moving with exact same speed and you may advice once the regarding q than they acceleration since the noticed because of the me was 0 and so the push would be 0.i am not saying capable understand this difficulty each time push non no and also at almost every other time it’s 0

ANSWER: The problem is your electronic and magnetized industries in a single frame out of reference won’t be the same such as several other moving physical stature. (It is special relativity.) In your case you first begin by a magnetic profession and zero electric career. Suppose that the newest magnetic community is in the y-guidance, B=jB, E=0, and also the speed away from q is in the x-guidance, v=iv. In the moving physical stature the latest fields would-be B’=j?B and you can E’=k?vB, where ?=1/ v(1-(v/c) dos ). Observe that E’=v x B’; together with force, once the present in new swinging physique try F’=qE’=qv x B’=k?qvB, to put it mildly. Mention, although not, you to F’ ?F , it differ of the a factor out-of ?; this is because push is considered become perhaps not Lorentz invariant and is not really a helpful quantity into the relativity.

QUESTION: Easily explore certain magnetized taverns, slashed him or her perfectly to ensure that I can place them together with her in order to form an entire world, with similar rod pointing outward, therefore the other pole pointing inwards, carry out I have a charismatic monopole target?

ANSWER: Think of your bars as dipoles of positive and negative magnetic charges (monopoles) separated by a distance d. The magnitude of the magnetic field B of a monopole is inversely proportional to the square of the distance r from the charge, B=kq/r 2 where k is some constant. In the drawing above the field at point p is B=B-q+B+q=kq[(1/(r-d) 2 -(1/r+d) 2 ]=4kqrd/[(r+d) 2 (r-d) 2 ]. The field does not look like a monopole because it falls off like 1/r 3 , not 1/r 2 .

Now, go through the career when roentgen>>d: B?4kqd/roentgen 3

QUESTION: Imagine We have a charge +q as there are a time P , Imagine I place a conductor between the charge +q and P . Since there are totally free electrons in it , Negative electrons flow towards the +q and you may equal self-confident costs within the conductor close P , Brand new conductor features fees distribution including good dipole. Anytime I do want to assess E profession on P . I will use superposition principle to acquire Elizabeth in the P due so you’re able to +q and you can Age due to dipole. However, Gauss’s legislation says one dipole doesn’t contribute almost anything to Age career during the P. Would you identify me personally ‘intuitively’ (Maybe not for the equations) as to why the dipole don’t contribute almost anything to the field during the P ?

  • Bạn đã yêu thích bài viết này!
  • Bạn đã copy link bài viết này!
Số điện thoại: 02633 666 777 Messenger LADO TAXI Zalo: 02633 666 777